(4/7)^(2x)=(343/64)^(x-1)

Solution for (4/7)^(2x)=(343/64)^(x-1) equation:

(4/7)^(2x)=(343/64)^(x-1)

We move all terms to the left:

(4/7)^(2x)-((343/64)^(x-1))=0


Domain of the equation: 7)^2x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 64)^(x-1))!=0

x∈R


We add all the numbers together, and all the variables

(+4/7)^2x-((+343/64)^(x-1))=0

We calculate fractions


(256^(x-1)))/7^2x*64)^(x-1)))+(-2401^2x/7^2x*64)^(x-1)))=0


We calculate terms in parentheses: +(256^(x-1)))/7^2x*64)^(x-1)))+(-2401^2x/7^2x*64)^(x-1))), so:

256^(x-1)))/7^2x*64)^(x-1)))+(-2401^2x/7^2x*64)^(x-1))

We can not solve this equation